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4x^2+70x-74=0
a = 4; b = 70; c = -74;
Δ = b2-4ac
Δ = 702-4·4·(-74)
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6084}=78$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-78}{2*4}=\frac{-148}{8} =-18+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+78}{2*4}=\frac{8}{8} =1 $
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